Palmola St. Hill
📍 488, Palmola Street, Lakeland, Polk County, Florida, 33803, United States
Useful Links
View this climb on other sites.
| Google Street View |
| Strava |
Climb Stats
The most common and useful climbing metrics.
| Climb (Meters) | 15.2 m |
| Distance (Kilometers) | 0.33 km |
| Average Gradient | 4.6% |
| Climb Category | Uncategorised |
Detailed Climb Stats
Stuff for climbing nerds.
| Distance (Miles) | 0.21 miles |
| Distance (Raw) | 331.4 m |
| Elevation High | 61.5 m |
| Elevation Low | 46.3 m |
| Maximum Gradient | 6.4% |
| Climb Difficulty Score | 1,521.13 |
Social Climbing
All the important climbing popularity information.
💪 There are 5,036 recorded attempts by 256 individual cyclists. |
📈 That's an average of 19.67 attempts per cyclist. |
😞 No one has favourited this climb. |
Climb Rank
How does this climb compare against every other climb in the world?
🗺 This climb ranks 2,084,793rd out of 2,710,652 worldwide cycling climbs. |
🧮 Ranked as the 241,035th most difficult cycling climb of all 337,250 climbs in United States. |
📉 Places 902nd out of 2,623 cycling climbs in Florida. |
⚖ Ranks 55th out of 155 cycling climbs in Polk County. |
⚖ Ranking 16th out of 35 cycling climbs in Lakeland. |
Site Update – October 2024
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