Indian Hill Rd climb Second half
📍 9908, Indian Hill Road, Auburn, Placer County, California, 95658, United States
Useful Links
View this climb on other sites.
| Google Street View |
| Strava |
Climb Stats
The most common and useful climbing metrics.
| Climb (Meters) | 68.6 m |
| Distance (Kilometers) | 1.48 km |
| Average Gradient | 4.6% |
| Climb Category | Uncategorised |
Detailed Climb Stats
Stuff for climbing nerds.
| Distance (Miles) | 0.92 miles |
| Distance (Raw) | 1,483.2 m |
| Elevation High | 407.6 m |
| Elevation Low | 339 m |
| Maximum Gradient | 7.3% |
| Climb Difficulty Score | 6,867.22 |
Social Climbing
All the important climbing popularity information.
💪 There are 68,134 recorded attempts by 5,311 individual cyclists. |
📈 That's an average of 12.83 attempts per cyclist. |
😞 No one has favourited this climb. |
Climb Rank
How does this climb compare against every other climb in the world?
🗺 This climb ranks 859,474th out of 2,710,652 worldwide cycling climbs. |
🧮 Ranked as the 75,599th most difficult cycling climb of all 337,250 climbs in United States. |
📉 Places 21,876th out of 66,571 cycling climbs in California. |
⚖ Ranks 238th out of 831 cycling climbs in Placer County. |
⚖ Ranking 31st out of 81 cycling climbs in Auburn. |
Site Update – October 2024
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